Release: 1.0.14 | Release Date: July 6, 2016

# SQLAlchemy 1.0 Documentation

# Mapping Class Inheritance Hierarchies

SQLAlchemy supports three forms of inheritance: single table inheritance, where several types of classes are represented by a single table, concrete table inheritance, where each type of class is represented by independent tables, and joined table inheritance, where the class hierarchy is broken up among dependent tables, each class represented by its own table that only includes those attributes local to that class.

The most common forms of inheritance are single and joined table, while concrete inheritance presents more configurational challenges.

When mappers are configured in an inheritance relationship, SQLAlchemy has the ability to load elements polymorphically, meaning that a single query can return objects of multiple types.

## Joined Table Inheritance

In joined table inheritance, each class along a particular classes’ list of parents is represented by a unique table. The total set of attributes for a particular instance is represented as a join along all tables in its inheritance path. Here, we first define the `Employee` class. This table will contain a primary key column (or columns), and a column for each attribute that’s represented by `Employee`. In this case it’s just `name`:

    class Employee(Base):
        __tablename__ = 'employee'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        type = Column(String(50))

        __mapper_args__ = {
            'polymorphic_identity':'employee',
            'polymorphic_on':type
        }

The mapped table also has a column called `type`. The purpose of this column is to act as the discriminator, and stores a value which indicates the type of object represented within the row. The column may be of any datatype, though string and integer are the most common.

Warning

Currently, only one discriminator column may be set, typically on the base-most class in the hierarchy. “Cascading” polymorphic columns are not yet supported.

The discriminator column is only needed if polymorphic loading is desired, as is usually the case. It is not strictly necessary that it be present directly on the base mapped table, and can instead be defined on a derived select statement that’s used when the class is queried; however, this is a much more sophisticated configuration scenario.

The mapping receives additional arguments via the `__mapper_args__` dictionary. Here the `type` column is explicitly stated as the discriminator column, and the polymorphic identity of `employee` is also given; this is the value that will be stored in the polymorphic discriminator column for instances of this class.

We next define `Engineer` and `Manager` subclasses of `Employee`. Each contains columns that represent the attributes unique to the subclass they represent. Each table also must contain a primary key column (or columns), and in most cases a foreign key reference to the parent table:

    class Engineer(Employee):
        __tablename__ = 'engineer'
        id = Column(Integer, ForeignKey('employee.id'), primary_key=True)
        engineer_name = Column(String(30))

        __mapper_args__ = {
            'polymorphic_identity':'engineer',
        }

    class Manager(Employee):
        __tablename__ = 'manager'
        id = Column(Integer, ForeignKey('employee.id'), primary_key=True)
        manager_name = Column(String(30))

        __mapper_args__ = {
            'polymorphic_identity':'manager',
        }

It is standard practice that the same column is used for both the role of primary key as well as foreign key to the parent table, and that the column is also named the same as that of the parent table. However, both of these practices are optional. Separate columns may be used for primary key and parent-relationship, the column may be named differently than that of the parent, and even a custom join condition can be specified between parent and child tables instead of using a foreign key.

Joined inheritance primary keys

One natural effect of the joined table inheritance configuration is that the identity of any mapped object can be determined entirely from the base table. This has obvious advantages, so SQLAlchemy always considers the primary key columns of a joined inheritance class to be those of the base table only. In other words, the `id` columns of both the `engineer` and `manager` tables are not used to locate `Engineer` or `Manager` objects - only the value in `employee.id` is considered. `engineer.id` and `manager.id` are still of course critical to the proper operation of the pattern overall as they are used to locate the joined row, once the parent row has been determined within a statement.

With the joined inheritance mapping complete, querying against `Employee` will return a combination of `Employee`, `Engineer` and `Manager` objects. Newly saved `Engineer`, `Manager`, and `Employee` objects will automatically populate the `employee.type` column with `engineer`, `manager`, or `employee`, as appropriate.

### Basic Control of Which Tables are Queried

The `orm.with_polymorphic()` function and the `with_polymorphic()` method of `Query` affects the specific tables which the `Query` selects from. Normally, a query such as this:

    session.query(Employee).all()

...selects only from the `employee` table. When loading fresh from the database, our joined-table setup will query from the parent table only, using SQL such as this:

    SELECT employee.id AS employee_id,
        employee.name AS employee_name, employee.type AS employee_type
    FROM employee
    []

As attributes are requested from those `Employee` objects which are represented in either the `engineer` or `manager` child tables, a second load is issued for the columns in that related row, if the data was not already loaded. So above, after accessing the objects you’d see further SQL issued along the lines of:

    SELECT manager.id AS manager_id,
        manager.manager_data AS manager_manager_data
    FROM manager
    WHERE ? = manager.id
    [5]
    SELECT engineer.id AS engineer_id,
        engineer.engineer_info AS engineer_engineer_info
    FROM engineer
    WHERE ? = engineer.id
    [2]

This behavior works well when issuing searches for small numbers of items, such as when using `Query.get()`, since the full range of joined tables are not pulled in to the SQL statement unnecessarily. But when querying a larger span of rows which are known to be of many types, you may want to actively join to some or all of the joined tables. The `with_polymorphic` feature provides this.

Telling our query to polymorphically load `Engineer` and `Manager` objects, we can use the `orm.with_polymorphic()` function to create a new aliased class which represents a select of the base table combined with outer joins to each of the inheriting tables:

    from sqlalchemy.orm import with_polymorphic

    eng_plus_manager = with_polymorphic(Employee, [Engineer, Manager])

    query = session.query(eng_plus_manager)

The above produces a query which joins the `employee` table to both the `engineer` and `manager` tables like the following:

    query.all()

    SELECT employee.id AS employee_id,
        engineer.id AS engineer_id,
        manager.id AS manager_id,
        employee.name AS employee_name,
        employee.type AS employee_type,
        engineer.engineer_info AS engineer_engineer_info,
        manager.manager_data AS manager_manager_data
    FROM employee
        LEFT OUTER JOIN engineer
        ON employee.id = engineer.id
        LEFT OUTER JOIN manager
        ON employee.id = manager.id
    []

The entity returned by `orm.with_polymorphic()` is an `AliasedClass` object, which can be used in a `Query` like any other alias, including named attributes for those attributes on the `Employee` class. In our example, `eng_plus_manager` becomes the entity that we use to refer to the three-way outer join above. It also includes namespaces for each class named in the list of classes, so that attributes specific to those subclasses can be called upon as well. The following example illustrates calling upon attributes specific to `Engineer` as well as `Manager` in terms of `eng_plus_manager`:

    eng_plus_manager = with_polymorphic(Employee, [Engineer, Manager])
    query = session.query(eng_plus_manager).filter(
                    or_(
                        eng_plus_manager.Engineer.engineer_info=='x',
                        eng_plus_manager.Manager.manager_data=='y'
                    )
                )

`orm.with_polymorphic()` accepts a single class or mapper, a list of classes/mappers, or the string `'*'` to indicate all subclasses:

    # join to the engineer table
    entity = with_polymorphic(Employee, Engineer)

    # join to the engineer and manager tables
    entity = with_polymorphic(Employee, [Engineer, Manager])

    # join to all subclass tables
    entity = with_polymorphic(Employee, '*')

    # use the 'entity' with a Query object
    session.query(entity).all()

It also accepts a third argument `selectable` which replaces the automatic join creation and instead selects directly from the selectable given. This feature is normally used with “concrete” inheritance, described later, but can be used with any kind of inheritance setup in the case that specialized SQL should be used to load polymorphically:

    # custom selectable
    employee = Employee.__table__
    manager = Manager.__table__
    engineer = Engineer.__table__
    entity = with_polymorphic(
                Employee,
                [Engineer, Manager],
                employee.outerjoin(manager).outerjoin(engineer)
            )

    # use the 'entity' with a Query object
    session.query(entity).all()

Note that if you only need to load a single subtype, such as just the `Engineer` objects, `orm.with_polymorphic()` is not needed since you would query against the `Engineer` class directly.

`Query.with_polymorphic()` has the same purpose as `orm.with_polymorphic()`, except is not as flexible in its usage patterns in that it only applies to the first full mapping, which then impacts all occurrences of that class or the target subclasses within the `Query`. For simple cases it might be considered to be more succinct:

    session.query(Employee).with_polymorphic([Engineer, Manager]).\
        filter(or_(Engineer.engineer_info=='w', Manager.manager_data=='q'))

New in version 0.8: `orm.with_polymorphic()`, an improved version of `Query.with_polymorphic()` method.

The mapper also accepts `with_polymorphic` as a configurational argument so that the joined-style load will be issued automatically. This argument may be the string `'*'`, a list of classes, or a tuple consisting of either, followed by a selectable:

    class Employee(Base):
        __tablename__ = 'employee'
        id = Column(Integer, primary_key=True)
        type = Column(String(20))

        __mapper_args__ = {
            'polymorphic_on':type,
            'polymorphic_identity':'employee',
            'with_polymorphic':'*'
        }

    class Engineer(Employee):
        __tablename__ = 'engineer'
        id = Column(Integer, ForeignKey('employee.id'), primary_key=True)
        __mapper_args__ = {'polymorphic_identity':'engineer'}

    class Manager(Employee):
        __tablename__ = 'manager'
        id = Column(Integer, ForeignKey('employee.id'), primary_key=True)
        __mapper_args__ = {'polymorphic_identity':'manager'}

The above mapping will produce a query similar to that of `with_polymorphic('*')` for every query of `Employee` objects.

Using `orm.with_polymorphic()` or `Query.with_polymorphic()` will override the mapper-level `with_polymorphic` setting.

`sqlalchemy.orm.``with_polymorphic`(base, classes, selectable=False, flat=False, polymorphic_on=None, aliased=False, innerjoin=False, _use_mapper_path=False, _existing_alias=None)

  Produce an `AliasedClass` construct which specifies columns for descendant mappers of the given base.

  New in version 0.8: `orm.with_polymorphic()` is in addition to the existing `Query` method `Query.with_polymorphic()`, which has the same purpose but is not as flexible in its usage.

  Using this method will ensure that each descendant mapper’s tables are included in the FROM clause, and will allow filter() criterion to be used against those tables. The resulting instances will also have those columns already loaded so that no “post fetch” of those columns will be required.

  See the examples at Basic Control of Which Tables are Queried.

  Parameters:

  - base – Base class to be aliased.
  - classes – a single class or mapper, or list of class/mappers, which inherit from the base class. Alternatively, it may also be the string `'*'`, in which case all descending mapped classes will be added to the FROM clause.
  - aliased – when True, the selectable will be wrapped in an alias, that is `(SELECT * FROM <fromclauses>) AS anon_1`. This can be important when using the with_polymorphic() to create the target of a JOIN on a backend that does not support parenthesized joins, such as SQLite and older versions of MySQL.
  - flat –
    Boolean, will be passed through to the
      `FromClause.alias()` call so that aliases of `Join` objects don’t include an enclosing SELECT. This can lead to more efficient queries in many circumstances. A JOIN against a nested JOIN will be rewritten as a JOIN against an aliased SELECT subquery on backends that don’t support this syntax.

    Setting `flat` to `True` implies the `aliased` flag is also `True`.

    New in version 0.9.0.

    See also

    `Join.alias()`

  - selectable – a table or select() statement that will be used in place of the generated FROM clause. This argument is required if any of the desired classes use concrete table inheritance, since SQLAlchemy currently cannot generate UNIONs among tables automatically. If used, the `selectable` argument must represent the full set of tables and columns mapped by every mapped class. Otherwise, the unaccounted mapped columns will result in their table being appended directly to the FROM clause which will usually lead to incorrect results.
  - polymorphic_on – a column to be used as the “discriminator” column for the given selectable. If not given, the polymorphic_on attribute of the base classes’ mapper will be used, if any. This is useful for mappings that don’t have polymorphic loading behavior by default.
  - innerjoin – if True, an INNER JOIN will be used. This should only be specified if querying for one specific subtype only

### Advanced Control of Which Tables are Queried

The `with_polymorphic` functions work fine for simplistic scenarios. However, direct control of table rendering is called for, such as the case when one wants to render to only the subclass table and not the parent table.

This use case can be achieved by using the mapped `Table` objects directly. For example, to query the name of employees with particular criterion:

    engineer = Engineer.__table__
    manager = Manager.__table__

    session.query(Employee.name).\
        outerjoin((engineer, engineer.c.employee_id==Employee.employee_id)).\
        outerjoin((manager, manager.c.employee_id==Employee.employee_id)).\
        filter(or_(Engineer.engineer_info=='w', Manager.manager_data=='q'))

The base table, in this case the “employees” table, isn’t always necessary. A SQL query is always more efficient with fewer joins. Here, if we wanted to just load information specific to manager or engineer, we can instruct `Query` to use only those tables. The `FROM` clause is determined by what’s specified in the `Session.query()`, `Query.filter()`, or `Query.select_from()` methods:

    session.query(Manager.manager_data).select_from(manager)

    session.query(engineer.c.id).\
            filter(engineer.c.engineer_info==manager.c.manager_data)

### Creating Joins to Specific Subtypes

The `of_type()` method is a helper which allows the construction of joins along `relationship()` paths while narrowing the criterion to specific subclasses. Suppose the `employees` table represents a collection of employees which are associated with a `Company` object. We’ll add a `company_id` column to the `employees` table and a new table `companies`:

    class Company(Base):
        __tablename__ = 'company'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        employees = relationship("Employee",
                        backref='company',
                        cascade='all, delete-orphan')

    class Employee(Base):
        __tablename__ = 'employee'
        id = Column(Integer, primary_key=True)
        type = Column(String(20))
        company_id = Column(Integer, ForeignKey('company.id'))
        __mapper_args__ = {
            'polymorphic_on':type,
            'polymorphic_identity':'employee',
            'with_polymorphic':'*'
        }

    class Engineer(Employee):
        __tablename__ = 'engineer'
        id = Column(Integer, ForeignKey('employee.id'), primary_key=True)
        engineer_info = Column(String(50))
        __mapper_args__ = {'polymorphic_identity':'engineer'}

    class Manager(Employee):
        __tablename__ = 'manager'
        id = Column(Integer, ForeignKey('employee.id'), primary_key=True)
        manager_data = Column(String(50))
        __mapper_args__ = {'polymorphic_identity':'manager'}

When querying from `Company` onto the `Employee` relationship, the `join()` method as well as the `any()` and `has()` operators will create a join from `company` to `employee`, without including `engineer` or `manager` in the mix. If we wish to have criterion which is specifically against the `Engineer` class, we can tell those methods to join or subquery against the joined table representing the subclass using the `of_type()` operator:

    session.query(Company).\
        join(Company.employees.of_type(Engineer)).\
        filter(Engineer.engineer_info=='someinfo')

A longhand version of this would involve spelling out the full target selectable within a 2-tuple:

    employee = Employee.__table__
    engineer = Engineer.__table__

    session.query(Company).\
        join((employee.join(engineer), Company.employees)).\
        filter(Engineer.engineer_info=='someinfo')

`of_type()` accepts a single class argument. More flexibility can be achieved either by joining to an explicit join as above, or by using the `orm.with_polymorphic()` function to create a polymorphic selectable:

    manager_and_engineer = with_polymorphic(
                                Employee, [Manager, Engineer],
                                aliased=True)

    session.query(Company).\
        join(manager_and_engineer, Company.employees).\
        filter(
            or_(manager_and_engineer.Engineer.engineer_info=='someinfo',
                manager_and_engineer.Manager.manager_data=='somedata')
        )

Above, we use the `aliased=True` argument with `orm.with_polymorhpic()` so that the right hand side of the join between `Company` and `manager_and_engineer` is converted into an aliased subquery. Some backends, such as SQLite and older versions of MySQL can’t handle a FROM clause of the following form:

    FROM x JOIN (y JOIN z ON <onclause>) ON <onclause>

Using `aliased=True` instead renders it more like:

    FROM x JOIN (SELECT * FROM y JOIN z ON <onclause>) AS anon_1 ON <onclause>

The above join can also be expressed more succinctly by combining `of_type()` with the polymorphic construct:

    manager_and_engineer = with_polymorphic(
                                Employee, [Manager, Engineer],
                                aliased=True)

    session.query(Company).\
        join(Company.employees.of_type(manager_and_engineer)).\
        filter(
            or_(manager_and_engineer.Engineer.engineer_info=='someinfo',
                manager_and_engineer.Manager.manager_data=='somedata')
        )

The `any()` and `has()` operators also can be used with `of_type()` when the embedded criterion is in terms of a subclass:

    session.query(Company).\
            filter(
                Company.employees.of_type(Engineer).
                    any(Engineer.engineer_info=='someinfo')
                ).all()

Note that the `any()` and `has()` are both shorthand for a correlated EXISTS query. To build one by hand looks like:

    session.query(Company).filter(
        exists([1],
            and_(Engineer.engineer_info=='someinfo',
                employees.c.company_id==companies.c.company_id),
            from_obj=employees.join(engineers)
        )
    ).all()

The EXISTS subquery above selects from the join of `employees` to `engineers`, and also specifies criterion which correlates the EXISTS subselect back to the parent `companies` table.

New in version 0.8: `of_type()` accepts `orm.aliased()` and `orm.with_polymorphic()` constructs in conjunction with `Query.join()`, `any()` and `has()`.

### Eager Loading of Specific or Polymorphic Subtypes

The `joinedload()`, `subqueryload()`, `contains_eager()` and other loading-related options also support paths which make use of `of_type()`. Below we load `Company` rows while eagerly loading related `Engineer` objects, querying the `employee` and `engineer` tables simultaneously:

    session.query(Company).\
        options(
            subqueryload(Company.employees.of_type(Engineer)).
            subqueryload("machines")
            )
        )

As is the case with `Query.join()`, `of_type()` also can be used with eager loading and `orm.with_polymorphic()` at the same time, so that all sub-attributes of all referenced subtypes can be loaded:

    manager_and_engineer = with_polymorphic(
                                Employee, [Manager, Engineer],
                                aliased=True)

    session.query(Company).\
        options(
            joinedload(Company.employees.of_type(manager_and_engineer))
            )
        )

New in version 0.8: `joinedload()`, `subqueryload()`, `contains_eager()` and related loader options support paths that are qualified with `of_type()`, supporting single target types as well as `orm.with_polymorphic()` targets.

Another option for the above query is to state the two subtypes separately; the `joinedload()` directive should detect this and create the above `with_polymorphic` construct automatically:

    session.query(Company).\
        options(
            joinedload(Company.employees.of_type(Manager)),
            joinedload(Company.employees.of_type(Engineer)),
            )
        )

New in version 1.0: Eager loaders such as `joinedload()` will create a polymorphic entity when multiple overlapping `of_type()` directives are encountered.

## Single Table Inheritance

Single table inheritance is where the attributes of the base class as well as all subclasses are represented within a single table. A column is present in the table for every attribute mapped to the base class and all subclasses; the columns which correspond to a single subclass are nullable. This configuration looks much like joined-table inheritance except there’s only one table. In this case, a `type` column is required, as there would be no other way to discriminate between classes. The table is specified in the base mapper only; for the inheriting classes, leave their `table` parameter blank:

    class Employee(Base):
        __tablename__ = 'employee'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        manager_data = Column(String(50))
        engineer_info = Column(String(50))
        type = Column(String(20))

        __mapper_args__ = {
            'polymorphic_on':type,
            'polymorphic_identity':'employee'
        }

    class Manager(Employee):
        __mapper_args__ = {
            'polymorphic_identity':'manager'
        }

    class Engineer(Employee):
        __mapper_args__ = {
            'polymorphic_identity':'engineer'
        }

Note that the mappers for the derived classes Manager and Engineer omit the `__tablename__`, indicating they do not have a mapped table of their own.

## Concrete Table Inheritance

This form of inheritance maps each class to a distinct table. As concrete inheritance has a bit more conceptual overhead, first we’ll illustrate what these tables look like as Core table metadata:

    employees_table = Table(
        'employee', metadata,
        Column('id', Integer, primary_key=True),
        Column('name', String(50)),
    )

    managers_table = Table(
        'manager', metadata,
        Column('id', Integer, primary_key=True),
        Column('name', String(50)),
        Column('manager_data', String(50)),
    )

    engineers_table = Table(
        'engineer', metadata,
        Column('id', Integer, primary_key=True),
        Column('name', String(50)),
        Column('engineer_info', String(50)),
    )

Notice in this case there is no `type` column; for polymorphic loading, additional steps will be needed in order to “manufacture” this information during a query.

Using classical mapping, we can map our three classes independently without any relationship between them; the fact that `Engineer` and `Manager` inherit from `Employee` does not have any impact on a classical mapping:

    class Employee(object):
        pass

    class Manager(Employee):
        pass

    class Engineer(Employee):
        pass

    mapper(Employee, employees_table)
    mapper(Manager, managers_table)
    mapper(Engineer, engineers_table)

However when using Declarative, Declarative assumes an inheritance mapping between the classes because they are already in an inheritance relationship. So to map our three classes declaratively, we must include the `orm.mapper.concrete` parameter within the `__mapper_args__`:

    class Employee(Base):
        __tablename__ = 'employee'

        id = Column(Integer, primary_key=True)
        name = Column(String(50))

    class Manager(Employee):
        __tablename__ = 'manager'

        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        manager_data = Column(String(50))

        __mapper_args__ = {
            'concrete': True
        }

    class Engineer(Employee):
        __tablename__ = 'engineer'

        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        engineer_info = Column(String(50))

        __mapper_args__ = {
            'concrete': True
        }

Two critical points should be noted:

- We must define all columns explicitly on each subclass, even those of the same name. A column such as `Employee.name` here is not copied out to the tables mapped by `Manager` or `Engineer` for us.
- while the `Engineer` and `Manager` classes are mapped in an inheritance relationship with `Employee`, they still do not include polymorphic loading.

### Concrete Polymorphic Loading

To load polymorphically, the `orm.mapper.with_polymorphic` argument is required, along with a selectable indicating how rows should be loaded. Polymorphic loading is most inefficient with concrete inheritance, so if we do seek this style of loading, while it is possible it’s less recommended. In the case of concrete inheritance, it means we must construct a UNION of all three tables.

First illustrating this with classical mapping, SQLAlchemy includes a helper function to create this UNION called `polymorphic_union()`, which will map all the different columns into a structure of selects with the same numbers and names of columns, and also generate a virtual `type` column for each subselect. The function is called after all three tables are declared, and is then combined with the mappers:

    from sqlalchemy.orm import polymorphic_union

    pjoin = polymorphic_union({
        'employee': employees_table,
        'manager': managers_table,
        'engineer': engineers_table
    }, 'type', 'pjoin')

    employee_mapper = mapper(Employee, employees_table,
                                        with_polymorphic=('*', pjoin),
                                        polymorphic_on=pjoin.c.type,
                                        polymorphic_identity='employee')
    manager_mapper = mapper(Manager, managers_table,
                                        inherits=employee_mapper,
                                        concrete=True,
                                        polymorphic_identity='manager')
    engineer_mapper = mapper(Engineer, engineers_table,
                                        inherits=employee_mapper,
                                        concrete=True,
                                        polymorphic_identity='engineer')

Upon select, the polymorphic union produces a query like this:

    session.query(Employee).all()

    SELECT
        pjoin.id AS pjoin_id,
        pjoin.name AS pjoin_name,
        pjoin.type AS pjoin_type,
        pjoin.manager_data AS pjoin_manager_data,
        pjoin.engineer_info AS pjoin_engineer_info
    FROM (
        SELECT
            employee.id AS id,
            employee.name AS name,
            CAST(NULL AS VARCHAR(50)) AS manager_data,
            CAST(NULL AS VARCHAR(50)) AS engineer_info,
            'employee' AS type
        FROM employee
        UNION ALL
        SELECT
            manager.id AS id,
            manager.name AS name,
            manager.manager_data AS manager_data,
            CAST(NULL AS VARCHAR(50)) AS engineer_info,
            'manager' AS type
        FROM manager
        UNION ALL
        SELECT
            engineer.id AS id,
            engineer.name AS name,
            CAST(NULL AS VARCHAR(50)) AS manager_data,
            engineer.engineer_info AS engineer_info,
            'engineer' AS type
        FROM engineer
    ) AS pjoin

The above UNION query needs to manufacture “NULL” columns for each subtable in order to accommodate for those columns that aren’t part of the mapping.

In order to map with concrete inheritance and polymorphic loading using Declarative, the challenge is to have the polymorphic union ready to go when the mappings are created. One way to achieve this is to continue to define the table metadata before the actual mapped classes, and specify them to each class using `__table__`:

    class Employee(Base):
        __table__ = employee_table
        __mapper_args__ = {
            'polymorphic_on':pjoin.c.type,
            'with_polymorphic': ('*', pjoin),
            'polymorphic_identity':'employee'
        }

    class Engineer(Employee):
        __table__ = engineer_table
        __mapper_args__ = {'polymorphic_identity':'engineer', 'concrete':True}

    class Manager(Employee):
        __table__ = manager_table
        __mapper_args__ = {'polymorphic_identity':'manager', 'concrete':True}

### Using the Declarative Helper Classes

Another way is to use a special helper class that takes on the fairly complicated task of deferring the production of `Mapper` objects until all table metadata has been collected, and the polymorphic union to which the mappers will be associated will be available. This is available via the `AbstractConcreteBase` and `ConcreteBase` classes. For our example here, we’re using a “concrete” base, e.g. an `Employee` row can exist by itself that is not an `Engineer` or a `Manager`. The mapping would look like:

    from sqlalchemy.ext.declarative import ConcreteBase

    class Employee(ConcreteBase, Base):
        __tablename__ = 'employee'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))

        __mapper_args__ = {
            'polymorphic_identity':'employee',
            'concrete':True
        }

    class Manager(Employee):
        __tablename__ = 'manager'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        manager_data = Column(String(40))

        __mapper_args__ = {
            'polymorphic_identity':'manager',
            'concrete':True
        }

    class Engineer(Employee):
        __tablename__ = 'engineer'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        engineer_info = Column(String(40))

        __mapper_args__ = {
            'polymorphic_identity':'engineer',
            'concrete':True
        }

There is also the option to use a so-called “abstract” base; where we wont actually have an `employee` table at all, and instead will only have `manager` and `engineer` tables. The `Employee` class will never be instantiated directly. The change here is that the base mapper is mapped directly to the “polymorphic union” selectable, which no longer includes the `employee` table. In classical mapping, this is:

    from sqlalchemy.orm import polymorphic_union

    pjoin = polymorphic_union({
        'manager': managers_table,
        'engineer': engineers_table
    }, 'type', 'pjoin')

    employee_mapper = mapper(Employee, pjoin,
                                        with_polymorphic=('*', pjoin),
                                        polymorphic_on=pjoin.c.type)
    manager_mapper = mapper(Manager, managers_table,
                                        inherits=employee_mapper,
                                        concrete=True,
                                        polymorphic_identity='manager')
    engineer_mapper = mapper(Engineer, engineers_table,
                                        inherits=employee_mapper,
                                        concrete=True,
                                        polymorphic_identity='engineer')

Using the Declarative helpers, the `AbstractConcreteBase` helper can produce this; the mapping would be:

    from sqlalchemy.ext.declarative import AbstractConcreteBase

    class Employee(AbstractConcreteBase, Base):
        pass

    class Manager(Employee):
        __tablename__ = 'manager'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        manager_data = Column(String(40))

        __mapper_args__ = {
            'polymorphic_identity':'manager',
            'concrete':True
        }

    class Engineer(Employee):
        __tablename__ = 'engineer'
        id = Column(Integer, primary_key=True)
        name = Column(String(50))
        engineer_info = Column(String(40))

        __mapper_args__ = {
            'polymorphic_identity':'engineer',
            'concrete':True
        }

See also

Concrete Table Inheritance - in the Declarative reference documentation

## Using Relationships with Inheritance

Both joined-table and single table inheritance scenarios produce mappings which are usable in `relationship()` functions; that is, it’s possible to map a parent object to a child object which is polymorphic. Similarly, inheriting mappers can have `relationship()` objects of their own at any level, which are inherited to each child class. The only requirement for relationships is that there is a table relationship between parent and child. An example is the following modification to the joined table inheritance example, which sets a bi-directional relationship between `Employee` and `Company`:

    employees_table = Table('employees', metadata,
        Column('employee_id', Integer, primary_key=True),
        Column('name', String(50)),
        Column('company_id', Integer, ForeignKey('companies.company_id'))
    )

    companies = Table('companies', metadata,
       Column('company_id', Integer, primary_key=True),
       Column('name', String(50)))

    class Company(object):
        pass

    mapper(Company, companies, properties={
       'employees': relationship(Employee, backref='company')
    })

### Relationships with Concrete Inheritance

In a concrete inheritance scenario, mapping relationships is more challenging since the distinct classes do not share a table. In this case, you can establish a relationship from parent to child if a join condition can be constructed from parent to child, if each child table contains a foreign key to the parent:

    companies = Table('companies', metadata,
       Column('id', Integer, primary_key=True),
       Column('name', String(50)))

    employees_table = Table('employees', metadata,
        Column('employee_id', Integer, primary_key=True),
        Column('name', String(50)),
        Column('company_id', Integer, ForeignKey('companies.id'))
    )

    managers_table = Table('managers', metadata,
        Column('employee_id', Integer, primary_key=True),
        Column('name', String(50)),
        Column('manager_data', String(50)),
        Column('company_id', Integer, ForeignKey('companies.id'))
    )

    engineers_table = Table('engineers', metadata,
        Column('employee_id', Integer, primary_key=True),
        Column('name', String(50)),
        Column('engineer_info', String(50)),
        Column('company_id', Integer, ForeignKey('companies.id'))
    )

    mapper(Employee, employees_table,
                    with_polymorphic=('*', pjoin),
                    polymorphic_on=pjoin.c.type,
                    polymorphic_identity='employee')

    mapper(Manager, managers_table,
                    inherits=employee_mapper,
                    concrete=True,
                    polymorphic_identity='manager')

    mapper(Engineer, engineers_table,
                    inherits=employee_mapper,
                    concrete=True,
                    polymorphic_identity='engineer')

    mapper(Company, companies, properties={
        'employees': relationship(Employee)
    })

The big limitation with concrete table inheritance is that `relationship()` objects placed on each concrete mapper do not propagate to child mappers. If you want to have the same `relationship()` objects set up on all concrete mappers, they must be configured manually on each. To configure back references in such a configuration the `back_populates` keyword may be used instead of `backref`, such as below where both `A(object)` and `B(A)` bidirectionally reference `C`:

    ajoin = polymorphic_union({
            'a':a_table,
            'b':b_table
        }, 'type', 'ajoin')

    mapper(A, a_table, with_polymorphic=('*', ajoin),
        polymorphic_on=ajoin.c.type, polymorphic_identity='a',
        properties={
            'some_c':relationship(C, back_populates='many_a')
    })
    mapper(B, b_table,inherits=A, concrete=True,
        polymorphic_identity='b',
        properties={
            'some_c':relationship(C, back_populates='many_a')
    })
    mapper(C, c_table, properties={
        'many_a':relationship(A, collection_class=set,
                                    back_populates='some_c'),
    })

## Using Inheritance with Declarative

Declarative makes inheritance configuration more intuitive. See the docs at Inheritance Configuration.